Solve 4(6r+3)geq20r-8

$$4 ( 6 r + 3 ) \geq 20 r - 8$$

Solve for r

$$r\geq -5$$

Solution Steps

Use the distributive property to multiply 4 by 6r+3.

$$24r+12\geq 20r-8$$

Subtract 20r from both sides.

$$24r+12-20r\geq -8$$

Combine 24r and -20r to get 4r.

$$4r+12\geq -8$$

Subtract 12 from both sides.

$$4r\geq -8-12$$

Subtract 12 from -8 to get -20.

$$4r\geq -20$$

Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.

$$r\geq \frac{-20}{4}$$

Divide -20 by 4 to get -5.

$$r\geq -5$$