Solve 4(5-3)+(45/7)(14)(3)^2-12[(-4)+(-6)]=

$$4 ( 5 - 3 ) + ( 45 / 7 ) ( 14 ) ( 3 ) ^ { 2 } - 12 [ ( - 4 ) + ( - 6 ) ] =$$

Evaluate

$$938$$

Solution Steps

Subtract 3 from 5 to get 2.

$$4\times 2+\frac{45}{7}\times 14\times 3^{2}-12\left(-4-6\right)$$

Multiply 4 and 2 to get 8.

$$8+\frac{45}{7}\times 14\times 3^{2}-12\left(-4-6\right)$$

Express \frac{45}{7}\times 14 as a single fraction.

$$8+\frac{45\times 14}{7}\times 3^{2}-12\left(-4-6\right)$$

Multiply 45 and 14 to get 630.

$$8+\frac{630}{7}\times 3^{2}-12\left(-4-6\right)$$

Divide 630 by 7 to get 90.

$$8+90\times 3^{2}-12\left(-4-6\right)$$

Calculate 3 to the power of 2 and get 9.

$$8+90\times 9-12\left(-4-6\right)$$

Multiply 90 and 9 to get 810.

$$8+810-12\left(-4-6\right)$$

Add 8 and 810 to get 818.

$$818-12\left(-4-6\right)$$

Subtract 6 from -4 to get -10.

$$818-12\left(-10\right)$$

Multiply 12 and -10 to get -120.

$$818-\left(-120\right)$$

The opposite of -120 is 120.

$$818+120$$

Add 818 and 120 to get 938.

$$938$$

Factor

$$2\times 7\times 67$$