Solve 4(4a+2b)(4a+3b)

$$4 ( 4 a + 2 b ) ( 4 a + 3 b )$$

Evaluate

$$8\left(2a+b\right)\left(4a+3b\right)$$

Solution Steps

Use the distributive property to multiply 4 by 4a+2b.

$$\left(16a+8b\right)\left(4a+3b\right)$$

Apply the distributive property by multiplying each term of 16a+8b by each term of 4a+3b.

$$64a^{2}+48ab+32ba+24b^{2}$$

Combine 48ab and 32ba to get 80ab.

$$64a^{2}+80ab+24b^{2}$$

Expand

$$64a^{2}+80ab+24b^{2}$$

Solution Steps

Use the distributive property to multiply 4 by 4a+2b.

$$\left(16a+8b\right)\left(4a+3b\right)$$

Apply the distributive property by multiplying each term of 16a+8b by each term of 4a+3b.

$$64a^{2}+48ab+32ba+24b^{2}$$

Combine 48ab and 32ba to get 80ab.

$$64a^{2}+80ab+24b^{2}$$