Solve 4(3x-5)+7geq8x+3

$$4 ( 3 x - 5 ) + 7 \geq 8 x + 3$$

Solve for x

$$x\geq 4$$

Solution Steps

Use the distributive property to multiply 4 by 3x-5.

$$12x-20+7\geq 8x+3$$

Add -20 and 7 to get -13.

$$12x-13\geq 8x+3$$

Subtract 8x from both sides.

$$12x-13-8x\geq 3$$

Combine 12x and -8x to get 4x.

$$4x-13\geq 3$$

Add 13 to both sides.

$$4x\geq 3+13$$

Add 3 and 13 to get 16.

$$4x\geq 16$$

Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.

$$x\geq \frac{16}{4}$$

Divide 16 by 4 to get 4.

$$x\geq 4$$