Solve 4(2x^2)+1

$$4 ( 2 x ^ { 2 } ) + 1$$

Differentiate w.r.t. x

$$16x$$

Steps Using Derivative Rule for Sum

Multiply 4 and 2 to get 8.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x^{2}+1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2\times 8x^{2-1}$$

Multiply 2 times 8.

$$16x^{2-1}$$

Subtract 1 from 2.

$$16x^{1}$$

For any term t, t^{1}=t.

$$16x$$

Evaluate

$$8x^{2}+1$$

Solution Steps

Multiply 4 and 2 to get 8.

$$8x^{2}+1$$