Solve 4(2-3(7)/2)=-2(7/2)-27

$$4 ( 2 - 3 \frac { ( 7 ) } { 2 } ) = - 2 ( \frac { 7 } { 2 } ) - 27$$

Verify

Solution Steps

Express 3\times \frac{7}{2} as a single fraction.

$$4\left(2-\frac{3\times 7}{2}\right)=-2\times \frac{7}{2}-27$$

Multiply 3 and 7 to get 21.

$$4\left(2-\frac{21}{2}\right)=-2\times \frac{7}{2}-27$$

Convert 2 to fraction \frac{4}{2}.

$$4\left(\frac{4}{2}-\frac{21}{2}\right)=-2\times \frac{7}{2}-27$$

Since \frac{4}{2} and \frac{21}{2} have the same denominator, subtract them by subtracting their numerators.

$$4\times \frac{4-21}{2}=-2\times \frac{7}{2}-27$$

Subtract 21 from 4 to get -17.

$$4\left(-\frac{17}{2}\right)=-2\times \frac{7}{2}-27$$

Express 4\left(-\frac{17}{2}\right) as a single fraction.

$$\frac{4\left(-17\right)}{2}=-2\times \frac{7}{2}-27$$

Multiply 4 and -17 to get -68.

$$\frac{-68}{2}=-2\times \frac{7}{2}-27$$

Divide -68 by 2 to get -34.

$$-34=-2\times \frac{7}{2}-27$$

Multiply -2 times \frac{7}{2}.

$$-34=-7-27$$

Subtract 27 from -7 to get -34.

$$-34=-34$$

Compare -34 and -34.

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