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4\times \frac{1}{6}x+40=\frac{5}{6}x-10
Use the distributive property to multiply 4 by \frac{1}{6}x+10.
\frac{4}{6}x+40=\frac{5}{6}x-10
Multiply 4 and \frac{1}{6} to get \frac{4}{6}.
\frac{2}{3}x+40=\frac{5}{6}x-10
Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.
\frac{2}{3}x+40-\frac{5}{6}x=-10
Subtract \frac{5}{6}x from both sides.
-\frac{1}{6}x+40=-10
Combine \frac{2}{3}x and -\frac{5}{6}x to get -\frac{1}{6}x.
-\frac{1}{6}x=-10-40
Subtract 40 from both sides.
-\frac{1}{6}x=-50
Subtract 40 from -10 to get -50.
x=-50\left(-6\right)
Multiply both sides by -6, the reciprocal of -\frac{1}{6}.
x=300
Multiply -50 and -6 to get 300.