Solve 4(1/3(2-4))=(3(2-4)-4/5)^2

$$4 ( \frac { 1 } { 3 } ( 2 - 4 ) ) = ( \frac { 3 ( 2 - 4 ) - 4 } { 5 } ) ^ { 2 }$$

Verify

Solution Steps

Multiply 4 and \frac{1}{3} to get \frac{4}{3}.

$$\frac{4}{3}\left(2-4\right)=\left(\frac{3\left(2-4\right)-4}{5}\right)^{2}$$

Subtract 4 from 2 to get -2.

$$\frac{4}{3}\left(-2\right)=\left(\frac{3\left(2-4\right)-4}{5}\right)^{2}$$

Multiply \frac{4}{3} and -2 to get -\frac{8}{3}.

$$-\frac{8}{3}=\left(\frac{3\left(2-4\right)-4}{5}\right)^{2}$$

Subtract 4 from 2 to get -2.

$$-\frac{8}{3}=\left(\frac{3\left(-2\right)-4}{5}\right)^{2}$$

Multiply 3 and -2 to get -6.

$$-\frac{8}{3}=\left(\frac{-6-4}{5}\right)^{2}$$

Subtract 4 from -6 to get -10.

$$-\frac{8}{3}=\left(\frac{-10}{5}\right)^{2}$$

Divide -10 by 5 to get -2.

$$-\frac{8}{3}=\left(-2\right)^{2}$$

Calculate -2 to the power of 2 and get 4.

$$-\frac{8}{3}=4$$

Convert 4 to fraction \frac{12}{3}.

$$-\frac{8}{3}=\frac{12}{3}$$

Compare -\frac{8}{3} and \frac{12}{3}.

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