Solve 4x^3-3x^2+4x-2divx-1

$$4 { x }^{ 3 } -3 { x }^{ 2 } +4x-2 \div x-1$$

Evaluate

$$4x^{3}-3x^{2}+4x-1-\frac{2}{x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 4x^{3}-3x^{2}+4x-1 times \frac{x}{x}.

$$\frac{\left(4x^{3}-3x^{2}+4x-1\right)x}{x}-\frac{2}{x}$$

Since \frac{\left(4x^{3}-3x^{2}+4x-1\right)x}{x} and \frac{2}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(4x^{3}-3x^{2}+4x-1\right)x-2}{x}$$

Do the multiplications in \left(4x^{3}-3x^{2}+4x-1\right)x-2.

$$\frac{4x^{4}-3x^{3}+4x^{2}-x-2}{x}$$

Factor

$$\frac{4x^{4}-3x^{3}+4x^{2}-x-2}{x}$$