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4\left(x^{3}+125z^{3}\right)
Factor out 4.
\left(x+5z\right)\left(x^{2}-5xz+25z^{2}\right)
Consider x^{3}+125z^{3}. Rewrite x^{3}+125z^{3} as x^{3}+\left(5z\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
4\left(x+5z\right)\left(x^{2}-5xz+25z^{2}\right)
Rewrite the complete factored expression.