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4x^{2}-100=4\left(x^{2}-6x+9\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
4x^{2}-100=4x^{2}-24x+36
Use the distributive property to multiply 4 by x^{2}-6x+9.
4x^{2}-100-4x^{2}=-24x+36
Subtract 4x^{2} from both sides.
-100=-24x+36
Combine 4x^{2} and -4x^{2} to get 0.
-24x+36=-100
Swap sides so that all variable terms are on the left hand side.
-24x=-100-36
Subtract 36 from both sides.
-24x=-136
Subtract 36 from -100 to get -136.
x=\frac{-136}{-24}
Divide both sides by -24.
x=\frac{17}{3}
Reduce the fraction \frac{-136}{-24} to lowest terms by extracting and canceling out -8.