Solve 4x^2=(3(y-1)-4(25)/5)

$$4 { x }^{ 2 } =( \frac{ 3(y-1)-4(25) }{ 5 } )$$

Solve for y

$$y=\frac{20x^{2}+103}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 5.

$$20x^{2}=3\left(y-1\right)-4\times 25$$

Use the distributive property to multiply 3 by y-1.

$$20x^{2}=3y-3-4\times 25$$

Multiply 4 and 25 to get 100.

$$20x^{2}=3y-3-100$$

Subtract 100 from -3 to get -103.

$$20x^{2}=3y-103$$

Swap sides so that all variable terms are on the left hand side.

$$3y-103=20x^{2}$$

Add 103 to both sides.

$$3y=20x^{2}+103$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{20x^{2}+103}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{20x^{2}+103}{3}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{15y-515}}{10}$$

$$x=\frac{\sqrt{15y-515}}{10}$$

Solve for x

$$x=\frac{\sqrt{15y-515}}{10}$$

$$x=-\frac{\sqrt{15y-515}}{10}\text{, }y\geq \frac{103}{3}$$