Solve 4x^2+6x+2x+3=4x^2+20x-25+10

$$4 { x }^{ 2 } +6x+2x+3=4 { x }^{ 2 } +20x-25+10$$

Solve for x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps for Solving Linear Equation

Combine 6x and 2x to get 8x.

$$4x^{2}+8x+3=4x^{2}+20x-25+10$$

Add -25 and 10 to get -15.

$$4x^{2}+8x+3=4x^{2}+20x-15$$

Subtract 4x^{2} from both sides.

$$4x^{2}+8x+3-4x^{2}=20x-15$$

Combine 4x^{2} and -4x^{2} to get 0.

$$8x+3=20x-15$$

Subtract 20x from both sides.

$$8x+3-20x=-15$$

Combine 8x and -20x to get -12x.

$$-12x+3=-15$$

Subtract 3 from both sides.

$$-12x=-15-3$$

Subtract 3 from -15 to get -18.

$$-12x=-18$$

Divide both sides by -12.

$$x=\frac{-18}{-12}$$

Reduce the fraction \frac{-18}{-12} to lowest terms by extracting and canceling out -6.

$$x=\frac{3}{2}$$