Solve 4x^2+2y-3=0

$$4 { x }^{ 2 } +2y-3=0$$

Solve for y

$$y=\frac{3}{2}-2x^{2}$$

Steps for Solving Linear Equation

Subtract 4x^{2} from both sides. Anything subtracted from zero gives its negation.

$$2y-3=-4x^{2}$$

Add 3 to both sides.

$$2y=-4x^{2}+3$$

The equation is in standard form.

$$2y=3-4x^{2}$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{3-4x^{2}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{3-4x^{2}}{2}$$

Divide -4x^{2}+3 by 2.

$$y=\frac{3}{2}-2x^{2}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{3-2y}}{2}$$

$$x=\frac{\sqrt{3-2y}}{2}$$

Solve for x

$$x=\frac{\sqrt{3-2y}}{2}$$

$$x=-\frac{\sqrt{3-2y}}{2}\text{, }y\leq \frac{3}{2}$$