Solve 45^3-1205^2+900*5

$$4 { 5 }^{ 3 } -120 { 5 }^{ 2 } +900 \cdot 5$$

Evaluate

$$2000$$

Solution Steps

Calculate 5 to the power of 3 and get 125.

$$4\times 125-120\times 5^{2}+900\times 5$$

Multiply 4 and 125 to get 500.

$$500-120\times 5^{2}+900\times 5$$

Calculate 5 to the power of 2 and get 25.

$$500-120\times 25+900\times 5$$

Multiply 120 and 25 to get 3000.

$$500-3000+900\times 5$$

Subtract 3000 from 500 to get -2500.

$$-2500+900\times 5$$

Multiply 900 and 5 to get 4500.

$$-2500+4500$$

Add -2500 and 4500 to get 2000.

$$2000$$

Factor

$$2^{4}\times 5^{3}$$