Solve 4left(2+5right)^2+6left(7+2right)^2

$$4 { \left(2+5 \right) }^{ 2 } +6 { \left(7+2 \right) }^{ 2 }$$

Evaluate

$$682$$

Solution Steps

Add 2 and 5 to get 7.

$$4\times 7^{2}+6\left(7+2\right)^{2}$$

Calculate 7 to the power of 2 and get 49.

$$4\times 49+6\left(7+2\right)^{2}$$

Multiply 4 and 49 to get 196.

$$196+6\left(7+2\right)^{2}$$

Add 7 and 2 to get 9.

$$196+6\times 9^{2}$$

Calculate 9 to the power of 2 and get 81.

$$196+6\times 81$$

Multiply 6 and 81 to get 486.

$$196+486$$

Add 196 and 486 to get 682.

$$682$$

Factor

$$2\times 11\times 31$$