Solve 4pi^pipipi22=Y^2x

$$4 { \pi }^{ \pi \pi \pi 22 } = { Y }^{ 2 } x$$

Solve for x

$$x=\frac{4\pi ^{22\pi ^{3}}}{Y^{2}}$$

$$Y\neq 0$$

Steps for Solving Linear Equation

Multiply \pi and \pi to get \pi ^{2}.

$$4\pi ^{\pi ^{2}\pi \times 22}=Y^{2}x$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$4\pi ^{\pi ^{3}\times 22}=Y^{2}x$$

Swap sides so that all variable terms are on the left hand side.

$$Y^{2}x=4\pi ^{\pi ^{3}\times 22}$$

The equation is in standard form.

$$Y^{2}x=4\pi ^{22\pi ^{3}}$$

Divide both sides by Y^{2}.

$$\frac{Y^{2}x}{Y^{2}}=\frac{4\pi ^{22\pi ^{3}}}{Y^{2}}$$

Dividing by Y^{2} undoes the multiplication by Y^{2}.

$$x=\frac{4\pi ^{22\pi ^{3}}}{Y^{2}}$$

Solve for Y (complex solution)

$$Y=-2\pi ^{11\pi ^{3}}x^{-\frac{1}{2}}$$

$$Y=2\pi ^{11\pi ^{3}}x^{-\frac{1}{2}}\text{, }x\neq 0$$

Solve for Y

$$Y=\frac{2\pi ^{11\pi ^{3}}}{\sqrt{x}}$$

$$Y=-\frac{2\pi ^{11\pi ^{3}}}{\sqrt{x}}\text{, }x>0$$