Solve 4*3+2-x^2=7

$$4 \times 3 + 2 - x ^ { 2 } = 7$$

Solve for x

$$x=\sqrt{7}\approx 2.645751311$$

$$x=-\sqrt{7}\approx -2.645751311$$

Steps by Finding Square Root

Multiply 4 and 3 to get 12.

$$12+2-x^{2}=7$$

Add 12 and 2 to get 14.

$$14-x^{2}=7$$

Subtract 14 from both sides.

$$-x^{2}=7-14$$

Subtract 14 from 7 to get -7.

$$-x^{2}=-7$$

Divide both sides by -1.

$$x^{2}=\frac{-7}{-1}$$

Fraction \frac{-7}{-1} can be simplified to 7 by removing the negative sign from both the numerator and the denominator.

$$x^{2}=7$$

Take the square root of both sides of the equation.

$$x=\sqrt{7} x=-\sqrt{7}$$

Steps Using the Quadratic Formula

Multiply 4 and 3 to get 12.

$$12+2-x^{2}=7$$

Add 12 and 2 to get 14.

$$14-x^{2}=7$$

Subtract 7 from both sides.

$$14-x^{2}-7=0$$

Subtract 7 from 14 to get 7.

$$7-x^{2}=0$$

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$-x^{2}+7=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 0 for b, and 7 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 7}}{2\left(-1\right)}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-1\right)\times 7}}{2\left(-1\right)}$$

Multiply -4 times -1.

$$x=\frac{0±\sqrt{4\times 7}}{2\left(-1\right)}$$

Multiply 4 times 7.

$$x=\frac{0±\sqrt{28}}{2\left(-1\right)}$$

Take the square root of 28.

$$x=\frac{0±2\sqrt{7}}{2\left(-1\right)}$$

Multiply 2 times -1.

$$x=\frac{0±2\sqrt{7}}{-2}$$

Now solve the equation x=\frac{0±2\sqrt{7}}{-2} when ± is plus.

$$x=-\sqrt{7}$$

Now solve the equation x=\frac{0±2\sqrt{7}}{-2} when ± is minus.

$$x=\sqrt{7}$$

The equation is now solved.

$$x=-\sqrt{7} x=\sqrt{7}$$