Solve 4*[(5-2)(1-3)]^2-(-10-2)^2

$$4 \times [ ( 5 - 2 ) ( 1 - 3 ) ] ^ { 2 } - ( - 10 - 2 ) ^ { 2 }$$

Evaluate

$$0$$

Solution Steps

Subtract 2 from 5 to get 3.

$$4\times \left(3\left(1-3\right)\right)^{2}-\left(-10-2\right)^{2}$$

Subtract 3 from 1 to get -2.

$$4\times \left(3\left(-2\right)\right)^{2}-\left(-10-2\right)^{2}$$

Multiply 3 and -2 to get -6.

$$4\left(-6\right)^{2}-\left(-10-2\right)^{2}$$

Calculate -6 to the power of 2 and get 36.

$$4\times 36-\left(-10-2\right)^{2}$$

Multiply 4 and 36 to get 144.

$$144-\left(-10-2\right)^{2}$$

Subtract 2 from -10 to get -12.

$$144-\left(-12\right)^{2}$$

Calculate -12 to the power of 2 and get 144.

$$144-144$$

Subtract 144 from 144 to get 0.

$$0$$

Factor

$$0$$