Solve 4*(3/28+3/4)=3*(3/4-3/28)

$$4 \times ( \frac{ 3 }{ 28 } + \frac{ 3 }{ 4 } )=3 \times ( \frac{ 3 }{ 4 } - \frac{ 3 }{ 28 } )$$

Verify

Solution Steps

Least common multiple of 28 and 4 is 28. Convert \frac{3}{28} and \frac{3}{4} to fractions with denominator 28.

$$4\left(\frac{3}{28}+\frac{21}{28}\right)=3\left(\frac{3}{4}-\frac{3}{28}\right)$$

Since \frac{3}{28} and \frac{21}{28} have the same denominator, add them by adding their numerators.

$$4\times \frac{3+21}{28}=3\left(\frac{3}{4}-\frac{3}{28}\right)$$

Add 3 and 21 to get 24.

$$4\times \frac{24}{28}=3\left(\frac{3}{4}-\frac{3}{28}\right)$$

Reduce the fraction \frac{24}{28} to lowest terms by extracting and canceling out 4.

$$4\times \frac{6}{7}=3\left(\frac{3}{4}-\frac{3}{28}\right)$$

Express 4\times \frac{6}{7} as a single fraction.

$$\frac{4\times 6}{7}=3\left(\frac{3}{4}-\frac{3}{28}\right)$$

Multiply 4 and 6 to get 24.

$$\frac{24}{7}=3\left(\frac{3}{4}-\frac{3}{28}\right)$$

Least common multiple of 4 and 28 is 28. Convert \frac{3}{4} and \frac{3}{28} to fractions with denominator 28.

$$\frac{24}{7}=3\left(\frac{21}{28}-\frac{3}{28}\right)$$

Since \frac{21}{28} and \frac{3}{28} have the same denominator, subtract them by subtracting their numerators.

$$\frac{24}{7}=3\times \frac{21-3}{28}$$

Subtract 3 from 21 to get 18.

$$\frac{24}{7}=3\times \frac{18}{28}$$

Reduce the fraction \frac{18}{28} to lowest terms by extracting and canceling out 2.

$$\frac{24}{7}=3\times \frac{9}{14}$$

Express 3\times \frac{9}{14} as a single fraction.

$$\frac{24}{7}=\frac{3\times 9}{14}$$

Multiply 3 and 9 to get 27.

$$\frac{24}{7}=\frac{27}{14}$$

Least common multiple of 7 and 14 is 14. Convert \frac{24}{7} and \frac{27}{14} to fractions with denominator 14.

$$\frac{48}{14}=\frac{27}{14}$$

Compare \frac{48}{14} and \frac{27}{14}.

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