Solve 4*4^4-3*4^3-9*4^2+4+2

$$4 \times { 4 }^{ 4 } -3 \times { 4 }^{ 3 } -9 \times { 4 }^{ 2 } +4+2$$

Evaluate

$$694$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 4 to get 5.

$$4^{5}-3\times 4^{3}-9\times 4^{2}+4+2$$

Calculate 4 to the power of 5 and get 1024.

$$1024-3\times 4^{3}-9\times 4^{2}+4+2$$

Calculate 4 to the power of 3 and get 64.

$$1024-3\times 64-9\times 4^{2}+4+2$$

Multiply 3 and 64 to get 192.

$$1024-192-9\times 4^{2}+4+2$$

Subtract 192 from 1024 to get 832.

$$832-9\times 4^{2}+4+2$$

Calculate 4 to the power of 2 and get 16.

$$832-9\times 16+4+2$$

Multiply 9 and 16 to get 144.

$$832-144+4+2$$

Subtract 144 from 832 to get 688.

$$688+4+2$$

Add 688 and 4 to get 692.

$$692+2$$

Add 692 and 2 to get 694.

$$694$$

Factor

$$2\times 347$$