Solve 4*1^4-3*1^3-9*1^2+1+2

$$4 \times { 1 }^{ 4 } -3 \times { 1 }^{ 3 } -9 \times { 1 }^{ 2 } +1+2$$

Evaluate

$$-5$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$4\times 1-3\times 1^{3}-9\times 1^{2}+1+2$$

Multiply 4 and 1 to get 4.

$$4-3\times 1^{3}-9\times 1^{2}+1+2$$

Calculate 1 to the power of 3 and get 1.

$$4-3\times 1-9\times 1^{2}+1+2$$

Multiply 3 and 1 to get 3.

$$4-3-9\times 1^{2}+1+2$$

Subtract 3 from 4 to get 1.

$$1-9\times 1^{2}+1+2$$

Calculate 1 to the power of 2 and get 1.

$$1-9\times 1+1+2$$

Multiply 9 and 1 to get 9.

$$1-9+1+2$$

Subtract 9 from 1 to get -8.

$$-8+1+2$$

Add -8 and 1 to get -7.

$$-7+2$$

Add -7 and 2 to get -5.

$$-5$$

Factor

$$-5$$