Solve 4sqrt{2y+1}-3=9

$$4 \sqrt { 2 y + 1 } - 3 = 9$$

Solve for y

$$y=4$$

Steps for Solving Radical Equations

Add 3 to both sides of the equation.

$$4\sqrt{2y+1}-3-\left(-3\right)=9-\left(-3\right)$$

Subtracting -3 from itself leaves 0.

$$4\sqrt{2y+1}=9-\left(-3\right)$$

Subtract -3 from 9.

$$4\sqrt{2y+1}=12$$

Divide both sides by 4.

$$\frac{4\sqrt{2y+1}}{4}=\frac{12}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$\sqrt{2y+1}=\frac{12}{4}$$

Divide 12 by 4.

$$\sqrt{2y+1}=3$$

Square both sides of the equation.

$$2y+1=9$$

Subtract 1 from both sides of the equation.

$$2y+1-1=9-1$$

Subtracting 1 from itself leaves 0.

$$2y=9-1$$

Subtract 1 from 9.

$$2y=8$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{8}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{8}{2}$$

Divide 8 by 2.

$$y=4$$