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4\sqrt{2}-2\times 2\sqrt{2}+\frac{3}{\sqrt{2}}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
4\sqrt{2}-4\sqrt{2}+\frac{3}{\sqrt{2}}
Multiply -2 and 2 to get -4.
\frac{3}{\sqrt{2}}
Combine 4\sqrt{2} and -4\sqrt{2} to get 0.
\frac{3\sqrt{2}}{\left(\sqrt{2}\right)^{2}}
Rationalize the denominator of \frac{3}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{3\sqrt{2}}{2}
The square of \sqrt{2} is 2.