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4\times 3\sqrt{2}+\sqrt{121}-5\sqrt{25}
Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.
12\sqrt{2}+\sqrt{121}-5\sqrt{25}
Multiply 4 and 3 to get 12.
12\sqrt{2}+11-5\sqrt{25}
Calculate the square root of 121 and get 11.
12\sqrt{2}+11-5\times 5
Calculate the square root of 25 and get 5.
12\sqrt{2}+11-25
Multiply -5 and 5 to get -25.
12\sqrt{2}-14
Subtract 25 from 11 to get -14.