Solve 4leq1/3x+8

$$4 \leq \frac{ 1 }{ 3 } x+8$$

Solve for x

$$x\geq -12$$

Solution Steps

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$\frac{1}{3}x+8\geq 4$$

Subtract 8 from both sides.

$$\frac{1}{3}x\geq 4-8$$

Subtract 8 from 4 to get -4.

$$\frac{1}{3}x\geq -4$$

Multiply both sides by 3, the reciprocal of \frac{1}{3}. Since \frac{1}{3} is positive, the inequality direction remains the same.

$$x\geq -4\times 3$$

Multiply -4 and 3 to get -12.

$$x\geq -12$$