Solve 4left(x+1right)<3left(x-3right)-x

$$4 \left( x+1 \right) < 3 \left( x-3 \right) -x$$

Solve for x

$$x<-\frac{13}{2}$$

Solution Steps

Use the distributive property to multiply 4 by x+1.

$$4x+4<3\left(x-3\right)-x$$

Use the distributive property to multiply 3 by x-3.

$$4x+4<3x-9-x$$

Combine 3x and -x to get 2x.

$$4x+4<2x-9$$

Subtract 2x from both sides.

$$4x+4-2x<-9$$

Combine 4x and -2x to get 2x.

$$2x+4<-9$$

Subtract 4 from both sides.

$$2x<-9-4$$

Subtract 4 from -9 to get -13.

$$2x<-13$$

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$x<-\frac{13}{2}$$