Solve 4left(7+4left(5*3-9right)right)-340/8

$$4 \left( 7+4 \left( 5 \cdot 3-9 \right) \right) -3 \frac{ 40 }{ 8 }$$

Evaluate

$$116$$

Solution Steps

Multiply 5 and 3 to get 15.

$$4\left(7+4\left(15-9\right)\right)-\frac{3\times 8+40}{8}$$

Subtract 9 from 15 to get 6.

$$4\left(7+4\times 6\right)-\frac{3\times 8+40}{8}$$

Multiply 4 and 6 to get 24.

$$4\left(7+24\right)-\frac{3\times 8+40}{8}$$

Add 7 and 24 to get 31.

$$4\times 31-\frac{3\times 8+40}{8}$$

Multiply 4 and 31 to get 124.

$$124-\frac{3\times 8+40}{8}$$

Multiply 3 and 8 to get 24.

$$124-\frac{24+40}{8}$$

Add 24 and 40 to get 64.

$$124-\frac{64}{8}$$

Divide 64 by 8 to get 8.

$$124-8$$

Subtract 8 from 124 to get 116.

$$116$$

Factor

$$2^{2}\times 29$$