Solve 43/4(2-5/12)

$$4 \frac{ 3 }{ 4 } (2- \frac{ 5 }{ 12 } )$$

Evaluate

$$\frac{361}{48}\approx 7.520833333$$

Solution Steps

Multiply 4 and 4 to get 16.

$$\frac{16+3}{4}\left(2-\frac{5}{12}\right)$$

Add 16 and 3 to get 19.

$$\frac{19}{4}\left(2-\frac{5}{12}\right)$$

Convert 2 to fraction \frac{24}{12}.

$$\frac{19}{4}\left(\frac{24}{12}-\frac{5}{12}\right)$$

Since \frac{24}{12} and \frac{5}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{19}{4}\times \frac{24-5}{12}$$

Subtract 5 from 24 to get 19.

$$\frac{19}{4}\times \frac{19}{12}$$

Multiply \frac{19}{4} times \frac{19}{12} by multiplying numerator times numerator and denominator times denominator.

$$\frac{19\times 19}{4\times 12}$$

Do the multiplications in the fraction \frac{19\times 19}{4\times 12}.

$$\frac{361}{48}$$

Factor

$$\frac{19 ^ {2}}{2 ^ {4} \cdot 3} = 7\frac{25}{48} = 7.520833333333333$$