Solve 42/4+21/3=

$$4 \frac{ 2 }{ 4 } +2 \frac{ 1 }{ 3 } =$$

Evaluate

$$\frac{41}{6}\approx 6.833333333$$

Solution Steps

Multiply 4 and 4 to get 16.

$$\frac{16+2}{4}+\frac{2\times 3+1}{3}$$

Add 16 and 2 to get 18.

$$\frac{18}{4}+\frac{2\times 3+1}{3}$$

Reduce the fraction \frac{18}{4} to lowest terms by extracting and canceling out 2.

$$\frac{9}{2}+\frac{2\times 3+1}{3}$$

Multiply 2 and 3 to get 6.

$$\frac{9}{2}+\frac{6+1}{3}$$

Add 6 and 1 to get 7.

$$\frac{9}{2}+\frac{7}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{9}{2} and \frac{7}{3} to fractions with denominator 6.

$$\frac{27}{6}+\frac{14}{6}$$

Since \frac{27}{6} and \frac{14}{6} have the same denominator, add them by adding their numerators.

$$\frac{27+14}{6}$$

Add 27 and 14 to get 41.

$$\frac{41}{6}$$

Factor

$$\frac{41}{2 \cdot 3} = 6\frac{5}{6} = 6.833333333333333$$