Solve 41/5*(32/7*(1+1/3))

$$4 \frac{ 1 }{ 5 } \times (3 \frac{ 2 }{ 7 } \times (1+ \frac{ 1 }{ 3 } ))$$

Evaluate

$$\frac{92}{5}=18.4$$

Solution Steps

Multiply 4 and 5 to get 20.

$$\frac{20+1}{5}\times \frac{3\times 7+2}{7}\left(1+\frac{1}{3}\right)$$

Add 20 and 1 to get 21.

$$\frac{21}{5}\times \frac{3\times 7+2}{7}\left(1+\frac{1}{3}\right)$$

Multiply 3 and 7 to get 21.

$$\frac{21}{5}\times \frac{21+2}{7}\left(1+\frac{1}{3}\right)$$

Add 21 and 2 to get 23.

$$\frac{21}{5}\times \frac{23}{7}\left(1+\frac{1}{3}\right)$$

Multiply \frac{21}{5} times \frac{23}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{21\times 23}{5\times 7}\left(1+\frac{1}{3}\right)$$

Do the multiplications in the fraction \frac{21\times 23}{5\times 7}.

$$\frac{483}{35}\left(1+\frac{1}{3}\right)$$

Reduce the fraction \frac{483}{35} to lowest terms by extracting and canceling out 7.

$$\frac{69}{5}\left(1+\frac{1}{3}\right)$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{69}{5}\left(\frac{3}{3}+\frac{1}{3}\right)$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{69}{5}\times \frac{3+1}{3}$$

Add 3 and 1 to get 4.

$$\frac{69}{5}\times \frac{4}{3}$$

Multiply \frac{69}{5} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{69\times 4}{5\times 3}$$

Do the multiplications in the fraction \frac{69\times 4}{5\times 3}.

$$\frac{276}{15}$$

Reduce the fraction \frac{276}{15} to lowest terms by extracting and canceling out 3.

$$\frac{92}{5}$$

Factor

$$\frac{2 ^ {2} \cdot 23}{5} = 18\frac{2}{5} = 18.4$$