Solve 41/3+61/4+1/2

$$4 \frac{ 1 }{ 3 } +6 \frac{ 1 }{ 4 } + \frac{ 1 }{ 2 }$$

Evaluate

$$\frac{133}{12}\approx 11.083333333$$

Solution Steps

Multiply 4 and 3 to get 12.

$$\frac{12+1}{3}+\frac{6\times 4+1}{4}+\frac{1}{2}$$

Add 12 and 1 to get 13.

$$\frac{13}{3}+\frac{6\times 4+1}{4}+\frac{1}{2}$$

Multiply 6 and 4 to get 24.

$$\frac{13}{3}+\frac{24+1}{4}+\frac{1}{2}$$

Add 24 and 1 to get 25.

$$\frac{13}{3}+\frac{25}{4}+\frac{1}{2}$$

Least common multiple of 3 and 4 is 12. Convert \frac{13}{3} and \frac{25}{4} to fractions with denominator 12.

$$\frac{52}{12}+\frac{75}{12}+\frac{1}{2}$$

Since \frac{52}{12} and \frac{75}{12} have the same denominator, add them by adding their numerators.

$$\frac{52+75}{12}+\frac{1}{2}$$

Add 52 and 75 to get 127.

$$\frac{127}{12}+\frac{1}{2}$$

Least common multiple of 12 and 2 is 12. Convert \frac{127}{12} and \frac{1}{2} to fractions with denominator 12.

$$\frac{127}{12}+\frac{6}{12}$$

Since \frac{127}{12} and \frac{6}{12} have the same denominator, add them by adding their numerators.

$$\frac{127+6}{12}$$

Add 127 and 6 to get 133.

$$\frac{133}{12}$$

Factor

$$\frac{7 \cdot 19}{2 ^ {2} \cdot 3} = 11\frac{1}{12} = 11.083333333333334$$