Solve 45/7*91/3

$$4 \frac { 5 } { 7 } \cdot 9 \frac { 1 } { 3 }$$

Evaluate

$$44$$

Solution Steps

Multiply 4 and 7 to get 28.

$$\frac{28+5}{7}\times \frac{9\times 3+1}{3}$$

Add 28 and 5 to get 33.

$$\frac{33}{7}\times \frac{9\times 3+1}{3}$$

Multiply 9 and 3 to get 27.

$$\frac{33}{7}\times \frac{27+1}{3}$$

Add 27 and 1 to get 28.

$$\frac{33}{7}\times \frac{28}{3}$$

Multiply \frac{33}{7} times \frac{28}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{33\times 28}{7\times 3}$$

Do the multiplications in the fraction \frac{33\times 28}{7\times 3}.

$$\frac{924}{21}$$

Divide 924 by 21 to get 44.

$$44$$

Factor

$$2^{2}\times 11$$