Solve 45/6-quad+27/9

$$4 \frac { 5 } { 6 } - \quad + 2 \frac { 7 } { 9 }$$

Evaluate

$$\frac{37}{18}\approx 2.055555556$$

Solution Steps

Multiply 4 and 6 to get 24.

$$\frac{24+5}{6}-\frac{2\times 9+7}{9}$$

Add 24 and 5 to get 29.

$$\frac{29}{6}-\frac{2\times 9+7}{9}$$

Multiply 2 and 9 to get 18.

$$\frac{29}{6}-\frac{18+7}{9}$$

Add 18 and 7 to get 25.

$$\frac{29}{6}-\frac{25}{9}$$

Least common multiple of 6 and 9 is 18. Convert \frac{29}{6} and \frac{25}{9} to fractions with denominator 18.

$$\frac{87}{18}-\frac{50}{18}$$

Since \frac{87}{18} and \frac{50}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{87-50}{18}$$

Subtract 50 from 87 to get 37.

$$\frac{37}{18}$$

Factor

$$\frac{37}{2 \cdot 3 ^ {2}} = 2\frac{1}{18} = 2.0555555555555554$$