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\frac{\left(4\times 8+3\right)\times 3}{8\left(2\times 3+1\right)}
Divide \frac{4\times 8+3}{8} by \frac{2\times 3+1}{3} by multiplying \frac{4\times 8+3}{8} by the reciprocal of \frac{2\times 3+1}{3}.
\frac{\left(32+3\right)\times 3}{8\left(2\times 3+1\right)}
Multiply 4 and 8 to get 32.
\frac{35\times 3}{8\left(2\times 3+1\right)}
Add 32 and 3 to get 35.
\frac{105}{8\left(2\times 3+1\right)}
Multiply 35 and 3 to get 105.
\frac{105}{8\left(6+1\right)}
Multiply 2 and 3 to get 6.
\frac{105}{8\times 7}
Add 6 and 1 to get 7.
\frac{105}{56}
Multiply 8 and 7 to get 56.
\frac{15}{8}
Reduce the fraction \frac{105}{56} to lowest terms by extracting and canceling out 7.