Solve 43/5-34/5+15/8=

$$4 \frac { 3 } { 5 } - 3 \frac { 4 } { 5 } + 1 \frac { 5 } { 8 } =$$

Evaluate

$$\frac{97}{40}=2.425$$

Solution Steps

Multiply 4 and 5 to get 20.

$$\frac{20+3}{5}-\frac{3\times 5+4}{5}+\frac{1\times 8+5}{8}$$

Add 20 and 3 to get 23.

$$\frac{23}{5}-\frac{3\times 5+4}{5}+\frac{1\times 8+5}{8}$$

Multiply 3 and 5 to get 15.

$$\frac{23}{5}-\frac{15+4}{5}+\frac{1\times 8+5}{8}$$

Add 15 and 4 to get 19.

$$\frac{23}{5}-\frac{19}{5}+\frac{1\times 8+5}{8}$$

Since \frac{23}{5} and \frac{19}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{23-19}{5}+\frac{1\times 8+5}{8}$$

Subtract 19 from 23 to get 4.

$$\frac{4}{5}+\frac{1\times 8+5}{8}$$

Multiply 1 and 8 to get 8.

$$\frac{4}{5}+\frac{8+5}{8}$$

Add 8 and 5 to get 13.

$$\frac{4}{5}+\frac{13}{8}$$

Least common multiple of 5 and 8 is 40. Convert \frac{4}{5} and \frac{13}{8} to fractions with denominator 40.

$$\frac{32}{40}+\frac{65}{40}$$

Since \frac{32}{40} and \frac{65}{40} have the same denominator, add them by adding their numerators.

$$\frac{32+65}{40}$$

Add 32 and 65 to get 97.

$$\frac{97}{40}$$

Factor

$$\frac{97}{2 ^ {3} \cdot 5} = 2\frac{17}{40} = 2.425$$