Solve 43/5+11/2=

$$4 \frac { 3 } { 5 } + 1 \frac { 1 } { 2 } =$$

Evaluate

$$\frac{61}{10}=6.1$$

Solution Steps

Multiply 4 and 5 to get 20.

$$\frac{20+3}{5}+\frac{1\times 2+1}{2}$$

Add 20 and 3 to get 23.

$$\frac{23}{5}+\frac{1\times 2+1}{2}$$

Multiply 1 and 2 to get 2.

$$\frac{23}{5}+\frac{2+1}{2}$$

Add 2 and 1 to get 3.

$$\frac{23}{5}+\frac{3}{2}$$

Least common multiple of 5 and 2 is 10. Convert \frac{23}{5} and \frac{3}{2} to fractions with denominator 10.

$$\frac{46}{10}+\frac{15}{10}$$

Since \frac{46}{10} and \frac{15}{10} have the same denominator, add them by adding their numerators.

$$\frac{46+15}{10}$$

Add 46 and 15 to get 61.

$$\frac{61}{10}$$

Factor

$$\frac{61}{2 \cdot 5} = 6\frac{1}{10} = 6.1$$