Solve 43/5+1/10-14/5=

$$4 \frac { 3 } { 5 } + \frac { 1 } { 10 } - 1 \frac { 4 } { 5 } =$$

Evaluate

$$\frac{29}{10}=2.9$$

Solution Steps

Multiply 4 and 5 to get 20.

$$\frac{20+3}{5}+\frac{1}{10}-\frac{1\times 5+4}{5}$$

Add 20 and 3 to get 23.

$$\frac{23}{5}+\frac{1}{10}-\frac{1\times 5+4}{5}$$

Least common multiple of 5 and 10 is 10. Convert \frac{23}{5} and \frac{1}{10} to fractions with denominator 10.

$$\frac{46}{10}+\frac{1}{10}-\frac{1\times 5+4}{5}$$

Since \frac{46}{10} and \frac{1}{10} have the same denominator, add them by adding their numerators.

$$\frac{46+1}{10}-\frac{1\times 5+4}{5}$$

Add 46 and 1 to get 47.

$$\frac{47}{10}-\frac{1\times 5+4}{5}$$

Multiply 1 and 5 to get 5.

$$\frac{47}{10}-\frac{5+4}{5}$$

Add 5 and 4 to get 9.

$$\frac{47}{10}-\frac{9}{5}$$

Least common multiple of 10 and 5 is 10. Convert \frac{47}{10} and \frac{9}{5} to fractions with denominator 10.

$$\frac{47}{10}-\frac{18}{10}$$

Since \frac{47}{10} and \frac{18}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{47-18}{10}$$

Subtract 18 from 47 to get 29.

$$\frac{29}{10}$$

Factor

$$\frac{29}{2 \cdot 5} = 2\frac{9}{10} = 2.9$$