Solve 43/4+24/12=

$$4 \frac { 3 } { 4 } + 2 \frac { 4 } { 12 } =$$

Evaluate

$$\frac{85}{12}\approx 7.083333333$$

Solution Steps

Multiply 4 and 4 to get 16.

$$\frac{16+3}{4}+\frac{2\times 12+4}{12}$$

Add 16 and 3 to get 19.

$$\frac{19}{4}+\frac{2\times 12+4}{12}$$

Multiply 2 and 12 to get 24.

$$\frac{19}{4}+\frac{24+4}{12}$$

Add 24 and 4 to get 28.

$$\frac{19}{4}+\frac{28}{12}$$

Reduce the fraction \frac{28}{12} to lowest terms by extracting and canceling out 4.

$$\frac{19}{4}+\frac{7}{3}$$

Least common multiple of 4 and 3 is 12. Convert \frac{19}{4} and \frac{7}{3} to fractions with denominator 12.

$$\frac{57}{12}+\frac{28}{12}$$

Since \frac{57}{12} and \frac{28}{12} have the same denominator, add them by adding their numerators.

$$\frac{57+28}{12}$$

Add 57 and 28 to get 85.

$$\frac{85}{12}$$

Factor

$$\frac{5 \cdot 17}{2 ^ {2} \cdot 3} = 7\frac{1}{12} = 7.083333333333333$$