Solve 42/8+51/6=

$$4 \frac { 2 } { 8 } + 5 \frac { 1 } { 6 } =$$

Evaluate

$$\frac{113}{12}\approx 9.416666667$$

Solution Steps

Multiply 4 and 8 to get 32.

$$\frac{32+2}{8}+\frac{5\times 6+1}{6}$$

Add 32 and 2 to get 34.

$$\frac{34}{8}+\frac{5\times 6+1}{6}$$

Reduce the fraction \frac{34}{8} to lowest terms by extracting and canceling out 2.

$$\frac{17}{4}+\frac{5\times 6+1}{6}$$

Multiply 5 and 6 to get 30.

$$\frac{17}{4}+\frac{30+1}{6}$$

Add 30 and 1 to get 31.

$$\frac{17}{4}+\frac{31}{6}$$

Least common multiple of 4 and 6 is 12. Convert \frac{17}{4} and \frac{31}{6} to fractions with denominator 12.

$$\frac{51}{12}+\frac{62}{12}$$

Since \frac{51}{12} and \frac{62}{12} have the same denominator, add them by adding their numerators.

$$\frac{51+62}{12}$$

Add 51 and 62 to get 113.

$$\frac{113}{12}$$

Factor

$$\frac{113}{2 ^ {2} \cdot 3} = 9\frac{5}{12} = 9.416666666666666$$