Solve 42/3-31/6+2

$$4 \frac { 2 } { 3 } - 3 \frac { 1 } { 6 } + 2$$

Evaluate

$$\frac{7}{2}=3.5$$

Solution Steps

Multiply 4 and 3 to get 12.

$$\frac{12+2}{3}-\frac{3\times 6+1}{6}+2$$

Add 12 and 2 to get 14.

$$\frac{14}{3}-\frac{3\times 6+1}{6}+2$$

Multiply 3 and 6 to get 18.

$$\frac{14}{3}-\frac{18+1}{6}+2$$

Add 18 and 1 to get 19.

$$\frac{14}{3}-\frac{19}{6}+2$$

Least common multiple of 3 and 6 is 6. Convert \frac{14}{3} and \frac{19}{6} to fractions with denominator 6.

$$\frac{28}{6}-\frac{19}{6}+2$$

Since \frac{28}{6} and \frac{19}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-19}{6}+2$$

Subtract 19 from 28 to get 9.

$$\frac{9}{6}+2$$

Reduce the fraction \frac{9}{6} to lowest terms by extracting and canceling out 3.

$$\frac{3}{2}+2$$

Convert 2 to fraction \frac{4}{2}.

$$\frac{3}{2}+\frac{4}{2}$$

Since \frac{3}{2} and \frac{4}{2} have the same denominator, add them by adding their numerators.

$$\frac{3+4}{2}$$

Add 3 and 4 to get 7.

$$\frac{7}{2}$$

Factor

$$\frac{7}{2} = 3\frac{1}{2} = 3.5$$