Solve 42/3-(3-2div0.125*1/12)

$$4 \frac { 2 } { 3 } - ( 3 - 2 \div 0.125 \times \frac { 1 } { 12 } )$$

Evaluate

$$3$$

Solution Steps

Multiply 4 and 3 to get 12.

$$\frac{12+2}{3}-\left(3-\frac{2}{0.125}\times \frac{1}{12}\right)$$

Add 12 and 2 to get 14.

$$\frac{14}{3}-\left(3-\frac{2}{0.125}\times \frac{1}{12}\right)$$

Expand \frac{2}{0.125} by multiplying both numerator and the denominator by 1000.

$$\frac{14}{3}-\left(3-\frac{2000}{125}\times \frac{1}{12}\right)$$

Divide 2000 by 125 to get 16.

$$\frac{14}{3}-\left(3-16\times \frac{1}{12}\right)$$

Multiply 16 and \frac{1}{12} to get \frac{16}{12}.

$$\frac{14}{3}-\left(3-\frac{16}{12}\right)$$

Reduce the fraction \frac{16}{12} to lowest terms by extracting and canceling out 4.

$$\frac{14}{3}-\left(3-\frac{4}{3}\right)$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{14}{3}-\left(\frac{9}{3}-\frac{4}{3}\right)$$

Since \frac{9}{3} and \frac{4}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14}{3}-\frac{9-4}{3}$$

Subtract 4 from 9 to get 5.

$$\frac{14}{3}-\frac{5}{3}$$

Since \frac{14}{3} and \frac{5}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14-5}{3}$$

Subtract 5 from 14 to get 9.

$$\frac{9}{3}$$

Divide 9 by 3 to get 3.

$$3$$

Factor

$$3$$