Solve 42/3div31/9=15

$$4 \frac { 2 } { 3 } \div 3 \frac { 1 } { 9 } = 15$$

Verify

Solution Steps

Divide \frac{4\times 3+2}{3} by \frac{3\times 9+1}{9} by multiplying \frac{4\times 3+2}{3} by the reciprocal of \frac{3\times 9+1}{9}.

$$\frac{\left(4\times 3+2\right)\times 9}{3\left(3\times 9+1\right)}=15$$

Cancel out 3 in both numerator and denominator.

$$\frac{3\left(2+3\times 4\right)}{1+3\times 9}=15$$

Multiply 3 and 4 to get 12.

$$\frac{3\left(2+12\right)}{1+3\times 9}=15$$

Add 2 and 12 to get 14.

$$\frac{3\times 14}{1+3\times 9}=15$$

Multiply 3 and 14 to get 42.

$$\frac{42}{1+3\times 9}=15$$

Multiply 3 and 9 to get 27.

$$\frac{42}{1+27}=15$$

Add 1 and 27 to get 28.

$$\frac{42}{28}=15$$

Reduce the fraction \frac{42}{28} to lowest terms by extracting and canceling out 14.

$$\frac{3}{2}=15$$

Convert 15 to fraction \frac{30}{2}.

$$\frac{3}{2}=\frac{30}{2}$$

Compare \frac{3}{2} and \frac{30}{2}.

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