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\frac{\left(4\times 3+2\right)\times 2}{3\left(3\times 2+1\right)}
Divide \frac{4\times 3+2}{3} by \frac{3\times 2+1}{2} by multiplying \frac{4\times 3+2}{3} by the reciprocal of \frac{3\times 2+1}{2}.
\frac{\left(12+2\right)\times 2}{3\left(3\times 2+1\right)}
Multiply 4 and 3 to get 12.
\frac{14\times 2}{3\left(3\times 2+1\right)}
Add 12 and 2 to get 14.
\frac{28}{3\left(3\times 2+1\right)}
Multiply 14 and 2 to get 28.
\frac{28}{3\left(6+1\right)}
Multiply 3 and 2 to get 6.
\frac{28}{3\times 7}
Add 6 and 1 to get 7.
\frac{28}{21}
Multiply 3 and 7 to get 21.
\frac{4}{3}
Reduce the fraction \frac{28}{21} to lowest terms by extracting and canceling out 7.