Solve 42/3div11/9

$$4 \frac { 2 } { 3 } \div 1 \frac { 1 } { 9 }$$

Evaluate

$$\frac{21}{5}=4.2$$

Solution Steps

Divide \frac{4\times 3+2}{3} by \frac{1\times 9+1}{9} by multiplying \frac{4\times 3+2}{3} by the reciprocal of \frac{1\times 9+1}{9}.

$$\frac{\left(4\times 3+2\right)\times 9}{3\left(1\times 9+1\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{3\left(2+3\times 4\right)}{1+9}$$

Multiply 3 and 4 to get 12.

$$\frac{3\left(2+12\right)}{1+9}$$

Add 2 and 12 to get 14.

$$\frac{3\times 14}{1+9}$$

Multiply 3 and 14 to get 42.

$$\frac{42}{1+9}$$

Add 1 and 9 to get 10.

$$\frac{42}{10}$$

Reduce the fraction \frac{42}{10} to lowest terms by extracting and canceling out 2.

$$\frac{21}{5}$$

Factor

$$\frac{3 \cdot 7}{5} = 4\frac{1}{5} = 4.2$$