Solve 41/6*91/7

$$4 \frac { 1 } { 6 } \cdot 9 \frac { 1 } { 7 }$$

Evaluate

$$\frac{800}{21}\approx 38.095238095$$

Solution Steps

Multiply 4 and 6 to get 24.

$$\frac{24+1}{6}\times \frac{9\times 7+1}{7}$$

Add 24 and 1 to get 25.

$$\frac{25}{6}\times \frac{9\times 7+1}{7}$$

Multiply 9 and 7 to get 63.

$$\frac{25}{6}\times \frac{63+1}{7}$$

Add 63 and 1 to get 64.

$$\frac{25}{6}\times \frac{64}{7}$$

Multiply \frac{25}{6} times \frac{64}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{25\times 64}{6\times 7}$$

Do the multiplications in the fraction \frac{25\times 64}{6\times 7}.

$$\frac{1600}{42}$$

Reduce the fraction \frac{1600}{42} to lowest terms by extracting and canceling out 2.

$$\frac{800}{21}$$

Factor

$$\frac{2 ^ {5} \cdot 5 ^ {2}}{3 \cdot 7} = 38\frac{2}{21} = 38.095238095238095$$