Solve 41/6*1/3-1/2*4/9=

$$4 \frac { 1 } { 6 } \cdot \frac { 1 } { 3 } - \frac { 1 } { 2 } \cdot \frac { 4 } { 9 } =$$

Evaluate

$$\frac{7}{6}\approx 1.166666667$$

Solution Steps

Multiply 4 and 6 to get 24.

$$\frac{24+1}{6}\times \frac{1}{3}-\frac{1}{2}\times \frac{4}{9}$$

Add 24 and 1 to get 25.

$$\frac{25}{6}\times \frac{1}{3}-\frac{1}{2}\times \frac{4}{9}$$

Multiply \frac{25}{6} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{25\times 1}{6\times 3}-\frac{1}{2}\times \frac{4}{9}$$

Do the multiplications in the fraction \frac{25\times 1}{6\times 3}.

$$\frac{25}{18}-\frac{1}{2}\times \frac{4}{9}$$

Multiply \frac{1}{2} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{25}{18}-\frac{1\times 4}{2\times 9}$$

Do the multiplications in the fraction \frac{1\times 4}{2\times 9}.

$$\frac{25}{18}-\frac{4}{18}$$

Since \frac{25}{18} and \frac{4}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-4}{18}$$

Subtract 4 from 25 to get 21.

$$\frac{21}{18}$$

Reduce the fraction \frac{21}{18} to lowest terms by extracting and canceling out 3.

$$\frac{7}{6}$$

Factor

$$\frac{7}{2 \cdot 3} = 1\frac{1}{6} = 1.1666666666666667$$