Solve 41/6+221/54=

$$4 \frac { 1 } { 6 } + 2 \frac { 21 } { 54 } =$$

Evaluate

$$\frac{59}{9}\approx 6.555555556$$

Solution Steps

Multiply 4 and 6 to get 24.

$$\frac{24+1}{6}+\frac{2\times 54+21}{54}$$

Add 24 and 1 to get 25.

$$\frac{25}{6}+\frac{2\times 54+21}{54}$$

Multiply 2 and 54 to get 108.

$$\frac{25}{6}+\frac{108+21}{54}$$

Add 108 and 21 to get 129.

$$\frac{25}{6}+\frac{129}{54}$$

Reduce the fraction \frac{129}{54} to lowest terms by extracting and canceling out 3.

$$\frac{25}{6}+\frac{43}{18}$$

Least common multiple of 6 and 18 is 18. Convert \frac{25}{6} and \frac{43}{18} to fractions with denominator 18.

$$\frac{75}{18}+\frac{43}{18}$$

Since \frac{75}{18} and \frac{43}{18} have the same denominator, add them by adding their numerators.

$$\frac{75+43}{18}$$

Add 75 and 43 to get 118.

$$\frac{118}{18}$$

Reduce the fraction \frac{118}{18} to lowest terms by extracting and canceling out 2.

$$\frac{59}{9}$$

Factor

$$\frac{59}{3 ^ {2}} = 6\frac{5}{9} = 6.555555555555555$$