Solve 41/5+23/10=

$$4 \frac { 1 } { 5 } + 2 \frac { 3 } { 10 } =$$

Evaluate

$$\frac{13}{2}=6.5$$

Solution Steps

Multiply 4 and 5 to get 20.

$$\frac{20+1}{5}+\frac{2\times 10+3}{10}$$

Add 20 and 1 to get 21.

$$\frac{21}{5}+\frac{2\times 10+3}{10}$$

Multiply 2 and 10 to get 20.

$$\frac{21}{5}+\frac{20+3}{10}$$

Add 20 and 3 to get 23.

$$\frac{21}{5}+\frac{23}{10}$$

Least common multiple of 5 and 10 is 10. Convert \frac{21}{5} and \frac{23}{10} to fractions with denominator 10.

$$\frac{42}{10}+\frac{23}{10}$$

Since \frac{42}{10} and \frac{23}{10} have the same denominator, add them by adding their numerators.

$$\frac{42+23}{10}$$

Add 42 and 23 to get 65.

$$\frac{65}{10}$$

Reduce the fraction \frac{65}{10} to lowest terms by extracting and canceling out 5.

$$\frac{13}{2}$$

Factor

$$\frac{13}{2} = 6\frac{1}{2} = 6.5$$