Solve 41/2+28/4-12/3=

$$4 \frac { 1 } { 2 } + 2 \frac { 8 } { 4 } - 1 \frac { 2 } { 3 } =$$

Evaluate

$$\frac{41}{6}\approx 6.833333333$$

Solution Steps

Multiply 4 and 2 to get 8.

$$\frac{8+1}{2}+\frac{2\times 4+8}{4}-\frac{1\times 3+2}{3}$$

Add 8 and 1 to get 9.

$$\frac{9}{2}+\frac{2\times 4+8}{4}-\frac{1\times 3+2}{3}$$

Multiply 2 and 4 to get 8.

$$\frac{9}{2}+\frac{8+8}{4}-\frac{1\times 3+2}{3}$$

Add 8 and 8 to get 16.

$$\frac{9}{2}+\frac{16}{4}-\frac{1\times 3+2}{3}$$

Divide 16 by 4 to get 4.

$$\frac{9}{2}+4-\frac{1\times 3+2}{3}$$

Convert 4 to fraction \frac{8}{2}.

$$\frac{9}{2}+\frac{8}{2}-\frac{1\times 3+2}{3}$$

Since \frac{9}{2} and \frac{8}{2} have the same denominator, add them by adding their numerators.

$$\frac{9+8}{2}-\frac{1\times 3+2}{3}$$

Add 9 and 8 to get 17.

$$\frac{17}{2}-\frac{1\times 3+2}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{17}{2}-\frac{3+2}{3}$$

Add 3 and 2 to get 5.

$$\frac{17}{2}-\frac{5}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{17}{2} and \frac{5}{3} to fractions with denominator 6.

$$\frac{51}{6}-\frac{10}{6}$$

Since \frac{51}{6} and \frac{10}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{51-10}{6}$$

Subtract 10 from 51 to get 41.

$$\frac{41}{6}$$

Factor

$$\frac{41}{2 \cdot 3} = 6\frac{5}{6} = 6.833333333333333$$